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05-03-2006, 09:42 AM
|  | Junior Member
My Mood:  | | | | | who here takes calculus?
quick question:
need the derivative of 2sin(5x-3)
thanx
__________________ Back from the dead, ready to shoot ur head off...
All in anonymity.  |
05-03-2006, 09:58 AM
|  | Senior Member | | Join Date: Mar 2006 Location: CSS 85.25.134.163:27016 Age: 17
Posts: 453
Points: 5.59 Donate | | | sorry no clue what you are talking about |
05-03-2006, 10:08 AM
| | | | i took calc several years ago but i think its 10cos(5x-3) |
05-03-2006, 10:15 AM
| | | Junior Member
My Mood: | | | | | THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!THANK YOU!
__________________ Back from the dead, ready to shoot ur head off...
All in anonymity. |
05-03-2006, 10:15 AM
|  | Senior Member
My Mood:  | | Join Date: Jan 2006 Location: stalkers...
Posts: 182
Points: 117.05 Donate | | | hm...nope dont know...and how can you have no posts if you made a post...
__________________ 100th Post 4/11 at 9:15 a.m. Forgive, Forget...Relive, Regret 
Got a 2 gig mem stick...then the next day the 4 gig came out...I was kinda mad...but I didnt buy the 2 gig so i sold it to get the 4 gig. |
05-03-2006, 10:21 AM
| | | | ya, apparently that post was an enigma |
05-03-2006, 10:57 AM
|  | Is Da Best PSP3D Member
My Mood:  | | Join Date: Dec 2005 Location: England
Posts: 651
Points: 1.40 Donate | | Quote: |
Originally Posted by Charun hm...nope dont know...and how can you have no posts if you made a post... | becuase were in the off-topic area where ure post count dosnet go up |
05-03-2006, 11:31 AM
|  | Teh h4x0r admin
My Mood:  | | Join Date: Feb 2006 Location: New York Age: 25
Posts: 961
Points: 9,999,500,270.79 Donate | | It's not cos(5x-3). You've got to use the chain rule. Remember? Derivative of f(g(x)) is not f'(g(x)).
f(x) = sin(x); g(x)=5x-3. Quote:
Theorem. Let F be the composition of two differentiable functions f and g; F(x) = f(g(x)). Then F is differentiable and
F'(x) = f '(g(x)) g '(x)
| Therefore, the derivative of sin(5x-3) is:
[ f'(x)=cos(x) ; g'(x)=5 ] 5*cos(5x-3).
You're welcome  |
05-03-2006, 08:57 PM
|  | Senior Member
My Mood:  | | Join Date: Feb 2006 Location: Flowermound, Tekas Age: 19
Posts: 492
Points: 18.83 Donate | | | I thought it was 10cos(5x-3)...I JUST TOOK A TEST LIKE YESTERDAY. Fuck.
__________________ I don't believe in signatures... |
05-03-2006, 09:20 PM
| | Member | | Join Date: Dec 2005
Posts: 38
Points: 18.38 Donate | | | it is 10cos(5x-3)
d (2sin(5x-3)) X d(5x-3)=2cos(5x-3) X 5= 10(cos(5x-3)) | |
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